XOR Functions
The XOR (exclusive-OR) functions create a result by combining each bit of one number with the corresponding bit of the other number. If a pair of corresponding bits are the same, the result for that bit position is 0; if they are different, the result is 1, as shown in the table.
|
XOR |
arg1 |
||
|
0 |
1 |
||
|
arg2 |
0 |
0 |
1 |
|
1 |
1 |
0 |
|
Sample Syntax
INT1XOR(arg1, arg2)
Remarks
| • | The XOR functions are commutative; that is, the order of the arguments does not affect the outcome. |
Examples
|
Function Input |
Result |
Comments |
|
INT1XOR(0,x) |
x |
0 has no bits set, so every bit set in x is set in the result. |
|
INT1XOR(0,x) |
-x |
-0 is mapped to 0 before being XORed to arg2. |
|
INT1XOR(-0,-x) |
x |
-0 is mapped to 0 before being XORed to arg2. |
|
INT1XOR(64,-64) |
-128 |
|
|
INT1XOR(64,-66) |
-2 |
|
|
INT1XOR(66,-64) |
-126 |
|
|
INT1XOR(-66,-64) |
126 |
|
|
INT1XOR(-1,127) |
-128 |
|
|
INT1XOR(-128,1) |
-127 |
|
|
. . . |
|
|
|
INT1XOR(-128,127) |
-1 |
|
|
INT1XOR(-128,-127) |
1 |
|
|
. . . |
|
|
|
INT1XOR(-128,-1) |
127 |
|